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9701-2021-mj-41-q06
May/June 2021 · Paper 41 · Question 6 · 18 marks
6(a) M1: ethanoic acid > butanoic acid > water > ethanol 4
M2: a reason given in terms of an electron donating or an electron withdrawing group for one of:
strengthening of O–H bond OR weakening of O–H bond OR stability of anion
Two out of the three alternatives M3, M4 and M5:
M3: ethanol: positive inductive effect / electron donating effect of ethyl / alkyl / R group
M4: butanoic acid: positive inductive effect / electron donating effect of propyl / alkyl / R group
M5: (either ethanoic or butanoic) acid: negative inductive effect of either C=O or carbonyl OR negative charge delocalised
over COO–
6(b)(i) 3
reagents and conditions observed change
Tollen’s reagent, warm silver mirror
test 1 OR
Fehling’s solution, warm (brick) red ppt / solid
test 2 acidified MnO –, warm decolourises OR bubbles
4
M1 / M2: reagents and conditions × 2
M3: observations both correct
© UCLES 2021 Page 12 of 17
6(b)(ii) 2
number of peaks in number of peaks in
compound
proton NMR carbon-13 NMR
HCO H 2 1
2
HO CCO H 1 1
2 2
HO CCH CH CO H 2 2
2 2 2 2
one mark for three, four or five correct
two marks for six correct
6(b)(iii) OH peak disappears AND proton / H exchanges with deuterium 1
6(c)(i) G = HOCH CH CH CH OH 2
2 2 2 2
H = NCCH CH CH CH CN
2 2 2 2
6(c)(ii) M1: step 1 NaOH(aq) + heat 4
M2: step 2 acidified KMnO + heat / acidified K Cr O + heat
4 2 2 7
M3: step 3 CN– / KCN / NaCN + heat
M4: step 4 LiAlH ALLOW Na in ethanol or H + Ni / Pd / Pt
4 2
6(d) 2
M1: correct displayed amide linkage
M2: the rest of the repeat unit correct including trailing bonds
© UCLES 2021 Page 13 of 17
Official mark scheme pages: 12, 13 · source PDF URL
9701-2021-mj-42-q08
May/June 2021 · Paper 42 · Question 8 · 10 marks
8(a) M1: 3
acyl chlorides > alkyl chlorides > aryl chlorides
fastest slowest
M2 / 3: Any two from:
• acyl chlorides carbon in C-Cl bond is more electron deficient since it is also attached to an oxygen atom OR C-Cl
bond is weakest / weakened in acyl chlorides since it is also attached to an oxygen atom / two electronegative atoms
• aryl chlorides (no hydrolysis) C-Cl bond is part of delocalised system / partially double bond character (so C-Cl bond is
stronger) OR lone pair / p-orbital on Cl delocalises with π ring (so C-Cl bond is stronger)
• alkyl chlorides C-Cl bond strengthened by electron donating effect / positive inductive effect of alkyl / R group (as
compared to acyl chlorides) OR carbon atom has a smaller δ+ and the C-Cl bond is stronger (than the C-Cl bond in
COCl) due to (the carbon) being only attached to one electronegative atom
8(b) 3
ALLOW amine salt for the third structure – mono or di ion
8(c)(i) 1
© UCLES 2021 Page 15 of 16
8(c)(ii) 3
chemical splitting pattern number of 1H atoms
environment of proton
shift (δ) (words required) responsible for the peak
0.95 alkane / CH doublet 6
3
1.90 alkane / CH multiplet 1
ALLOW alkyne
2.20 R / alkyl / CH next to doublet 2
2
C=O / COOH
mark as • • • • • •
© UCLES 2021 Page 16 of 16
Official mark scheme pages: 15, 16 · source PDF URL
9701-2021-mj-43-q06
May/June 2021 · Paper 43 · Question 6 · 18 marks
6(a) M1: ethanoic acid > butanoic acid > water > ethanol 4
M2: a reason given in terms of an electron donating or an electron withdrawing group for one of:
strengthening of O–H bond OR weakening of O–H bond OR stability of anion
Two out of the three alternatives M3, M4 and M5:
M3: ethanol: positive inductive effect / electron donating effect of ethyl / alkyl / R group
M4: butanoic acid: positive inductive effect / electron donating effect of propyl / alkyl / R group
M5: (either ethanoic or butanoic) acid: negative inductive effect of either C=O or carbonyl OR negative charge delocalised
over COO–
6(b)(i) 3
reagents and conditions observed change
Tollen’s reagent, warm silver mirror
test 1 OR
Fehling’s solution, warm (brick) red ppt / solid
test 2 acidified MnO –, warm decolourises OR bubbles
4
M1 / M2: reagents and conditions × 2
M3: observations both correct
© UCLES 2021 Page 12 of 17
6(b)(ii) 2
number of peaks in number of peaks in
compound
proton NMR carbon-13 NMR
HCO H 2 1
2
HO CCO H 1 1
2 2
HO CCH CH CO H 2 2
2 2 2 2
one mark for three, four or five correct
two marks for six correct
6(b)(iii) OH peak disappears AND proton / H exchanges with deuterium 1
6(c)(i) G = HOCH CH CH CH OH 2
2 2 2 2
H = NCCH CH CH CH CN
2 2 2 2
6(c)(ii) M1: step 1 NaOH(aq) + heat 4
M2: step 2 acidified KMnO + heat / acidified K Cr O + heat
4 2 2 7
M3: step 3 CN– / KCN / NaCN + heat
M4: step 4 LiAlH ALLOW Na in ethanol or H + Ni / Pd / Pt
4 2
6(d) 2
M1: correct displayed amide linkage
M2: the rest of the repeat unit correct including trailing bonds
© UCLES 2021 Page 13 of 17
Official mark scheme pages: 12, 13 · source PDF URL
9701-2022-mj-41-q05
May/June 2022 · Paper 41 · Question 5 · 16 marks
5(a) M1 benzoic acid > phenol > phenylmethanol 3
M2 / M3 Any two of:
in benzoic acid negative inductive effect of C=O AND O-H bond is weakened
OR due to delocalisation of minus charge by C=O / 2O carboxylate ion is stabilised
in phenol lone pair on oxygen is delocalised into the ring AND O-H bond is weakened
in phenyl methanol positive inductive effect of CH group AND O-H bond is strengthened
2
5(b) 3
benzoic acid phenylmethanol phenol
Na(s)
NaOH(aq)
Na CO (aq)
2 3
Three correct for one mark, six correct for two marks, nine correct for three marks
© UCLES 2022 Page 10 of 15
5(c)(i) POCl and HCl AND SO and HCl 1
3 2
5(c)(ii) all the by-products / SO and HCl are gaseous OR no liquid by-products formed 1
2
5(d)(i) 4
On the left-hand side:
lone pair on O
correct arrow from O to C (of C=O)
dipole on C=O
correct arrow on C=O
M1 / M2 Two correct for one mark, four correct for two marks
On the right-hand side:
M3 correct intermediate
M4 arrow from lone pair on O– to C-O bond AND arrow from C-Cl to Cl
5(d)(ii) addition-elimination 1
© UCLES 2022 Page 11 of 15
5(e)(i) 2
OR
5(e)(ii) hydrolysis OR heating in dilute acid / alkali 1
Question Answer Marks
Official mark scheme pages: 10, 11, 12 · source PDF URL
9701-2022-mj-43-q05
May/June 2022 · Paper 43 · Question 5 · 16 marks
5(a) M1 benzoic acid > phenol > phenylmethanol 3
M2 / M3 Any two of:
in benzoic acid negative inductive effect of C=O AND O-H bond is weakened
OR due to delocalisation of minus charge by C=O / 2O carboxylate ion is stabilised
in phenol lone pair on oxygen is delocalised into the ring AND O-H bond is weakened
in phenyl methanol positive inductive effect of CH group AND O-H bond is strengthened
2
5(b) 3
benzoic acid phenylmethanol phenol
Na(s)
NaOH(aq)
Na CO (aq)
2 3
Three correct for one mark, six correct for two marks, nine correct for three marks
© UCLES 2022 Page 10 of 15
5(c)(i) POCl and HCl AND SO and HCl 1
3 2
5(c)(ii) all the by-products / SO and HCl are gaseous OR no liquid by-products formed 1
2
5(d)(i) 4
On the left-hand side:
lone pair on O
correct arrow from O to C (of C=O)
dipole on C=O
correct arrow on C=O
M1 / M2 Two correct for one mark, four correct for two marks
On the right-hand side:
M3 correct intermediate
M4 arrow from lone pair on O– to C-O bond AND arrow from C-Cl to Cl
5(d)(ii) addition-elimination 1
© UCLES 2022 Page 11 of 15
5(e)(i) 2
OR
5(e)(ii) hydrolysis OR heating in dilute acid / alkali 1
Question Answer Marks
Official mark scheme pages: 10, 11, 12 · source PDF URL
9701-2023-mj-42-q06
May/June 2023 · Paper 42 · Question 6 · 8 marks
6(a)(i) 5 / five 1
6(a)(ii) M1 benefit: 2
higher biological efficiency / activity (of the drug)
OR less side effects
OR smaller dose required (as drug more potent)
M2 disadvantage:
the need to separate (a racemic mixture into a single stereoisomer)
OR lower yield (of biologically active molecule/product)
OR need a chiral catalyst / enzyme (in the synthesis so expensive)
6(b)(i) carboxylic acid/carboxyl, ester, amide, amine 2
Any two [1], all four [2]
© UCLES 2023 Page 14 of 19
6(b)(ii) 3
3 [1] for each structure
Question Answer Marks
Official mark scheme pages: 14, 15 · source PDF URL
9701-2023-on-41-q09
Oct/Nov 2023 · Paper 41 · Question 9 · 13 marks
9(a)(i) 1
[1]
9(a)(ii) hot (alkaline) KMnO / MnO – [1] 2
4 4
SOCl OR PCl OR PCl + heat[1]
2 5 3
9(a)(iii) oxidation [1] 2
(nucleophilic) substitution
© UCLES 2023 Page 16 of 18
9(b)(i)
10
and HCl
The red numbers refer to points 1 to 10 in the verbal MS that follows.
box one: 4
• 1 dipole on C=O
• 2 curly arrow from O of phenol to C of acyl chloride
• 3 curly arrow from bond of C=O to O of acyl chloride
box two:
• 4 curly arrow from O-H bond to what was O of phenol
• 5 curly arrow from C-Cl bond to what was Cl of acyl chloride
• 6 curly arrow from O to reform C=O
• 7 + charge on what was O of phenol
• 8 – charge on what was O of acyl chloride
• 9 curly arrow start close to LP for bullet 3 OR 6 (from LP on O)
box three:
• 10 HCl / H+Cl –
any two [1] any five [2] any eight [3] all ten [4]
9(b)(ii) (nucleophilic) addition-elimination [1] 1
© UCLES 2023 Page 17 of 18
9(c) chlorobenzene, chloroethane, benzoyl chloride [1] u / c 3
explanation linked to their order
• correct link to: strengthening (ArCl / RCl) C-Cl bond
OR weakening (RCOCl) C-Cl bond
OR C-Cl bond has partially double bond character (ArCl)
OR C-Cl is more difficult to break (linked correctly)
chlorobenzene:
• lone pair / p-orbital on Cl overlaps / delocalised / incorporated with ring
benzoyl chloride:
• C of C-Cl has most electron deficient
OR has an electronegative oxygen atom
/ two electronegative atoms / electron withdrawing C=O group
chloroethane
• electron donating effect / positive inductive effect of alkyl / R group
any two [1] any three [2]
© UCLES 2023 Page 18 of 18
Official mark scheme pages: 16, 17, 18 · source PDF URL
9701-2023-on-43-q09
Oct/Nov 2023 · Paper 43 · Question 9 · 13 marks
9(a)(i) 1
[1]
9(a)(ii) hot (alkaline) KMnO / MnO – [1] 2
4 4
SOCl OR PCl OR PCl + heat[1]
2 5 3
9(a)(iii) oxidation [1] 2
(nucleophilic) substitution
© UCLES 2023 Page 16 of 18
9(b)(i)
10
and HCl
The red numbers refer to points 1 to 10 in the verbal MS that follows.
box one: 4
• 1 dipole on C=O
• 2 curly arrow from O of phenol to C of acyl chloride
• 3 curly arrow from bond of C=O to O of acyl chloride
box two:
• 4 curly arrow from O-H bond to what was O of phenol
• 5 curly arrow from C-Cl bond to what was Cl of acyl chloride
• 6 curly arrow from O to reform C=O
• 7 + charge on what was O of phenol
• 8 – charge on what was O of acyl chloride
• 9 curly arrow start close to LP for bullet 3 OR 6 (from LP on O)
box three:
• 10 HCl / H+Cl –
any two [1] any five [2] any eight [3] all ten [4]
9(b)(ii) (nucleophilic) addition-elimination [1] 1
© UCLES 2023 Page 17 of 18
9(c) chlorobenzene, chloroethane, benzoyl chloride [1] u / c 3
explanation linked to their order
• correct link to: strengthening (ArCl / RCl) C-Cl bond
OR weakening (RCOCl) C-Cl bond
OR C-Cl bond has partially double bond character (ArCl)
OR C-Cl is more difficult to break (linked correctly)
chlorobenzene:
• lone pair / p-orbital on Cl overlaps / delocalised / incorporated with ring
benzoyl chloride:
• C of C-Cl has most electron deficient
OR has an electronegative oxygen atom
/ two electronegative atoms / electron withdrawing C=O group
chloroethane
• electron donating effect / positive inductive effect of alkyl / R group
any two [1] any three [2]
© UCLES 2023 Page 18 of 18
Official mark scheme pages: 16, 17, 18 · source PDF URL
9701-2024-on-42-q06
Oct/Nov 2024 · Paper 42 · Question 6 · 12 marks
6(a)(i) ClOCCOCl [1] 1
6(a)(ii) PCl / PCl [1] 1
3 5
6(b) oxygen [1] 2
acidified KMnO [1]
4
6(c) C=O are electron withdrawing / electronegative [1] 2
weakens O–H bond OR stabilises anion [1]
6(d)(i) 1
[1]
6(d)(ii) step 1: CH Cl + AlCl [1] 2
3 3
step 2: hot alkaline KMnO [1]
4
© Cambridge University Press & Assessment 2024 Page 9 of 12
6(d)(iii) 2
correctly displayed ester linkage [1]
rest of structure [1]
6(d)(iv) condensation AND ester [1] 1
Question Answer Marks
Official mark scheme pages: 9, 10 · source PDF URL
9701-2025-mj-41-q10
May/June 2025 · Paper 41 · Question 10 · 7 marks
10(a) 1
10(b) M1: reagent 1:Fehling’s OR Tollens’ reagent 4
M2: acidified MnO –
4
observation when treated observation when treated
with reagent 1 with reagent 2
propanoic acid no change no change
methanoic acid red ppt OR silver mirror colourless
ethanedioic acid no change colourless
M3 / M4: One completely correct column [1] both completely correct columns [2]
10(c) M1: chlorine atoms are electron withdrawing / electronegative 2
M2: weakening O–H bond OR stabilising conjugate base
© Cambridge University Press & Assessment 2025 Page 16 of 16
Official mark scheme pages: 16 · source PDF URL
9701-2025-mj-43-q10
May/June 2025 · Paper 43 · Question 10 · 7 marks
10(a) 1
10(b) M1: reagent 1:Fehling’s OR Tollens’ reagent 4
M2: acidified MnO –
4
observation when treated observation when treated
with reagent 1 with reagent 2
propanoic acid no change no change
methanoic acid red ppt OR silver mirror colourless
ethanedioic acid no change colourless
M3 / M4: One completely correct column [1] both completely correct columns [2]
10(c) M1: chlorine atoms are electron withdrawing / electronegative 2
M2: weakening O–H bond OR stabilising conjugate base
© Cambridge University Press & Assessment 2025 Page 16 of 16
Official mark scheme pages: 16 · source PDF URL
9701-2025-mj-44-q07
May/June 2025 · Paper 44 · Question 7 · 11 marks
7(a) M1: benzoic acid > phenol > ethanol 3
M2 / M3: any two [1] any three [2]
• correct link of acidity once AND weakens O—H / OH bond / hydroxyl bond / -O-H
OR H+ more easily lost / (carboxylate) anion stabilised u / c
• (benzoic acid) due to negative inductive effect / electron withdrawing effect AND of C=O / COOH / carboxyl
• (phenol) as lone pair / p-orbital (electrons) on oxygen (on phenol) / AND overlap / delocalised into the ring / π-system
• (ethanol) alkyl / ethyl / R group AND is electron donating / positive inductive effect
7(b) 2
Each correct structure = [1]
7(c)(i) ethyl propanoate 1
© Cambridge University Press & Assessment 2025 Page 15 of 17
7(c)(ii) 4
M1 / M2: any two [1] all four [2]
• lone pair on O
• correct arrow from (lone pair) O to C (of C=O)
• dipole on C=O
• correct arrow on C=O
M3: correct intermediate
M4: arrow from lone pair or charge on O– to C-O bond AND arrow from C-Cl to Cl
7(c)(iii) (nucleophilic) addition – elimination 1
Question Answer Marks
Official mark scheme pages: 15, 16 · source PDF URL
9701-2025-on-41-q07
Oct/Nov 2025 · Paper 41 · Question 7 · 12 marks
7(a) M1: ClCH
2
COOH BrCH
2
COOH CH
3
COOH CH
3
CH
2
OH 4
most acidic least acidic
M2: electron withdrawing groups / electronegative groups / negative inductive effect
AND weakens O–H bond / more stable anion
OR
electron donating groups / positive inductive effect AND strengthens O-H bond / less stable anion
M3 M4:
• chlorine is more electron-withdrawing / electronegative than bromine (related to XCH COOH)
2
• electron withdrawing of C=O / negative inductive effect of C=O (related to COOH)
• positive inductive effect / electron donating of alkyl / ethyl / R group (related to ROH)
any two [1], all three [2]
7(b) M1: 2
M2: CO
2
© Cambridge University Press & Assessment 2025 Page 14 of 19
7(c)(i) 2
M1: correct displayed amide bond with C=O, (C H )−N and (C–)C=O
6 5
M2: rest of the structure correct with continuation bonds
7(c)(ii) 1
7(d)(i) 2
M1:
M2:
© Cambridge University Press & Assessment 2025 Page 15 of 19
7(d)(ii) HNO (and HCl) AND ⩽10 °C 1
2
OR
NaNO AND HCl AND ⩽10 °C
2
Question Answer Marks
Official mark scheme pages: 14, 15, 16 · source PDF URL
9701-2025-on-41-q08
Oct/Nov 2025 · Paper 41 · Question 8 · 13 marks
8(a)(i) NO group directs to 3 (and 5) / meta position AND due to being an electron-withdrawing / electronegative group 1
2
8(a)(ii) HNO + H SO → NO + + HSO – + H O 1
3 2 4 2 4 2
OR HNO + 2H SO → NO + + 2HSO – + H O+
3 2 4 2 4 3
8(b)(i) 1
8(b)(ii) M1: (reaction 1) ethanoyl chloride / CH
3
COCl AND AlCl3 2
M2: (reaction 2) 2-bromopropane / (CH ) CHBr AND FeBr
3 2 3
8(c) M1: 3
with C H Br no change / no precipitate AND
6 5
with C H CH Br cream precipitate
6 5 2
in C H Br
6 5
M2: lone pair / p-orbital on Br delocalised / overlaps with ring / system
M3: C–Br bond stronger / has partially double bond character
© Cambridge University Press & Assessment 2025 Page 16 of 19
8(d)(i) (nucleophilic) addition–elimination 1
8(d)(ii) 4
M1 M2:
• lone pair on O
• curly arrow from (lone pair) O (in H O) to C (of C=O)
2
• correct dipole on C=O
• curly arrow from the C=O bond to O atom
any two [1], all four [2]
M3: correct intermediate
M4: curly arrow from (lone pair on) O(–) to C–O bond AND curly arrow from C–Br to Br
Question Answer Marks
Official mark scheme pages: 16, 17 · source PDF URL
9701-2025-on-43-q07
Oct/Nov 2025 · Paper 43 · Question 7 · 12 marks
7(a) M1: ClCH
2
COOH BrCH
2
COOH CH
3
COOH CH
3
CH
2
OH 4
most acidic least acidic
M2: electron withdrawing groups / electronegative groups / negative inductive effect
AND weakens O–H bond / more stable anion
OR
electron donating groups / positive inductive effect AND strengthens O-H bond / less stable anion
M3 M4:
• chlorine is more electron-withdrawing / electronegative than bromine (related to XCH COOH)
2
• electron withdrawing of C=O / negative inductive effect of C=O (related to COOH)
• positive inductive effect / electron donating of alkyl / ethyl / R group (related to ROH)
any two [1], all three [2]
7(b) M1: 2
M2: CO
2
© Cambridge University Press & Assessment 2025 Page 14 of 19
7(c)(i) 2
M1: correct displayed amide bond with C=O, (C H )−N and (C–)C=O
6 5
M2: rest of the structure correct with continuation bonds
7(c)(ii) 1
7(d)(i) 2
M1:
M2:
© Cambridge University Press & Assessment 2025 Page 15 of 19
7(d)(ii) HNO (and HCl) AND ⩽10 °C 1
2
OR
NaNO AND HCl AND ⩽10 °C
2
Question Answer Marks
Official mark scheme pages: 14, 15, 16 · source PDF URL
9701-2025-on-43-q08
Oct/Nov 2025 · Paper 43 · Question 8 · 13 marks
8(a)(i) NO group directs to 3 (and 5) / meta position AND due to being an electron-withdrawing / electronegative group 1
2
8(a)(ii) HNO + H SO → NO + + HSO – + H O 1
3 2 4 2 4 2
OR HNO + 2H SO → NO + + 2HSO – + H O+
3 2 4 2 4 3
8(b)(i) 1
8(b)(ii) M1: (reaction 1) ethanoyl chloride / CH
3
COCl AND AlCl3 2
M2: (reaction 2) 2-bromopropane / (CH ) CHBr AND FeBr
3 2 3
8(c) M1: 3
with C H Br no change / no precipitate AND
6 5
with C H CH Br cream precipitate
6 5 2
in C H Br
6 5
M2: lone pair / p-orbital on Br delocalised / overlaps with ring / system
M3: C–Br bond stronger / has partially double bond character
© Cambridge University Press & Assessment 2025 Page 16 of 19
8(d)(i) (nucleophilic) addition–elimination 1
8(d)(ii) 4
M1 M2:
• lone pair on O
• curly arrow from (lone pair) O (in H O) to C (of C=O)
2
• correct dipole on C=O
• curly arrow from the C=O bond to O atom
any two [1], all four [2]
M3: correct intermediate
M4: curly arrow from (lone pair on) O(–) to C–O bond AND curly arrow from C–Br to Br
Question Answer Marks
Official mark scheme pages: 16, 17 · source PDF URL
9701-2025-on-44-q08
Oct/Nov 2025 · Paper 44 · Question 8 · 11 marks
8(a) • chlorobenzene is less reactive than ethanoyl chloride 2
• p orbital / lone pair on Cl / –Cl will overlap / delocalise into the ring
OR C of COCl has most electron deficient OR has an electronegative oxygen atom / two electronegative atoms / electron
withdrawing C=O group
• due to partial double C–Cl bond
OR C–Cl bond strengthened (more) / stronger bond between Cl and benzene / ring
OR C–Cl weakened in ROCl
any two [1], all three [2]
8(b)(i) • nitrile 2
• amide
• ketone / carbonyl
• ester
any two [1], all four [2]
8(b)(ii) 8 / eight 1
8(b)(iii) no need to separate optical isomers 1
© Cambridge University Press & Assessment 2025 Page 15 of 16
8(c) 3
M1: amide bond hydrolysed and COO– and NH formed
2
M2: nitrile bond hydrolysed and COO– formed
M3: ester bond hydrolysed and COO– and OH formed
8(d)(i) percentage = 100 28 / (28 + 58 + 13 + 42) = 19.9(%) min 2sf 1
8(d)(ii) D is attracted more strongly to the stationary phase / forms stronger intermolecular forces with the stationary phase 1
© Cambridge University Press & Assessment 2025 Page 16 of 16
Official mark scheme pages: 15, 16 · source PDF URL
9701-2026-m-42-q04
March 2026 · Paper 42 · Question 4 · 14 marks
4(a)(i) two separate half-life readings quoted t ≅ 6000 (s) 250 2
½
same / constant half-life (∴ first order with respect to [ester])
4(a)(ii) tangent seen at t = 0 AND initial rate (from gradient of tangent) ≅ 0.24 / 8750 = 2.74 10–5 (mol dm–3 s–1) min 2sf 1
4(a)(iii) rate = k [CH COOCH ] [H+] 2
3 3
mol–1 dm3 s–1
4(b)(i) • reaction 6 / CH COCl goes to completion / non-reversible 2
3
• reaction 7 / CH COOH is an equilibrium (reaction) / reversible
3
• reaction 6 has a gas formed AND has a greater S / entropy is increased (so more feasible)
any two [2]
4(b)(ii) 4
M1: correct arrow from lone pair on O (in CH OH) to C (of C=O)
3
M2: correct dipole on C=O AND correct arrow from the C=O bond to O atom
M3: correct intermediate (both charges present)
M4: arrow from (lone pair on) O(–) to C–O bond AND arrow from C-Cl bond to Cl
© Cambridge University Press & Assessment 2026 Page 14 of 18
4(c) M1: chlorobenzene < chloroethane < ethanoyl chloride 3
M2 & M3: Any two from:
(acyl chlorides easier than alkyl chlorides)
• has two electronegative atom groups/an extra electronegative atom / an electronegative oxygen / electron withdrawing
C=O AND so C (of C=O) highly / more electron deficient / C-Cl bond weak(est)
(aryl chlorides hardest)
• LP / lone pair / p-orbital on Cl/chlorine AND overlaps / delocalised with ring / system AND (C-Cl) bond is
strengthened / has partial double bond character
(alkyl chlorides easier than aryl chlorides)
• carbon is bonded to an electronegative atom / Cl / not bonded to electronegative O AND so has less electron deficient
carbon
OR
• C-Cl bond strengthened AND by positive inductive effect of alkyl / R group
Question Answer Marks
Official mark scheme pages: 14, 15 · source PDF URL